Integrand size = 15, antiderivative size = 80 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=-\frac {a^3 \left (a+b x^4\right )^{5/4}}{5 b^4}+\frac {a^2 \left (a+b x^4\right )^{9/4}}{3 b^4}-\frac {3 a \left (a+b x^4\right )^{13/4}}{13 b^4}+\frac {\left (a+b x^4\right )^{17/4}}{17 b^4} \]
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Time = 0.04 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=-\frac {a^3 \left (a+b x^4\right )^{5/4}}{5 b^4}+\frac {a^2 \left (a+b x^4\right )^{9/4}}{3 b^4}+\frac {\left (a+b x^4\right )^{17/4}}{17 b^4}-\frac {3 a \left (a+b x^4\right )^{13/4}}{13 b^4} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} \text {Subst}\left (\int x^3 \sqrt [4]{a+b x} \, dx,x,x^4\right ) \\ & = \frac {1}{4} \text {Subst}\left (\int \left (-\frac {a^3 \sqrt [4]{a+b x}}{b^3}+\frac {3 a^2 (a+b x)^{5/4}}{b^3}-\frac {3 a (a+b x)^{9/4}}{b^3}+\frac {(a+b x)^{13/4}}{b^3}\right ) \, dx,x,x^4\right ) \\ & = -\frac {a^3 \left (a+b x^4\right )^{5/4}}{5 b^4}+\frac {a^2 \left (a+b x^4\right )^{9/4}}{3 b^4}-\frac {3 a \left (a+b x^4\right )^{13/4}}{13 b^4}+\frac {\left (a+b x^4\right )^{17/4}}{17 b^4} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.76 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=\frac {\sqrt [4]{a+b x^4} \left (-128 a^4+32 a^3 b x^4-20 a^2 b^2 x^8+15 a b^3 x^{12}+195 b^4 x^{16}\right )}{3315 b^4} \]
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Time = 4.20 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.59
method | result | size |
gosper | \(-\frac {\left (b \,x^{4}+a \right )^{\frac {5}{4}} \left (-195 b^{3} x^{12}+180 a \,b^{2} x^{8}-160 a^{2} b \,x^{4}+128 a^{3}\right )}{3315 b^{4}}\) | \(47\) |
pseudoelliptic | \(-\frac {\left (b \,x^{4}+a \right )^{\frac {5}{4}} \left (-195 b^{3} x^{12}+180 a \,b^{2} x^{8}-160 a^{2} b \,x^{4}+128 a^{3}\right )}{3315 b^{4}}\) | \(47\) |
trager | \(-\frac {\left (-195 x^{16} b^{4}-15 a \,b^{3} x^{12}+20 a^{2} b^{2} x^{8}-32 a^{3} b \,x^{4}+128 a^{4}\right ) \left (b \,x^{4}+a \right )^{\frac {1}{4}}}{3315 b^{4}}\) | \(58\) |
risch | \(-\frac {\left (-195 x^{16} b^{4}-15 a \,b^{3} x^{12}+20 a^{2} b^{2} x^{8}-32 a^{3} b \,x^{4}+128 a^{4}\right ) \left (b \,x^{4}+a \right )^{\frac {1}{4}}}{3315 b^{4}}\) | \(58\) |
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Time = 0.27 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.71 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=\frac {{\left (195 \, b^{4} x^{16} + 15 \, a b^{3} x^{12} - 20 \, a^{2} b^{2} x^{8} + 32 \, a^{3} b x^{4} - 128 \, a^{4}\right )} {\left (b x^{4} + a\right )}^{\frac {1}{4}}}{3315 \, b^{4}} \]
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Time = 0.65 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.38 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=\begin {cases} - \frac {128 a^{4} \sqrt [4]{a + b x^{4}}}{3315 b^{4}} + \frac {32 a^{3} x^{4} \sqrt [4]{a + b x^{4}}}{3315 b^{3}} - \frac {4 a^{2} x^{8} \sqrt [4]{a + b x^{4}}}{663 b^{2}} + \frac {a x^{12} \sqrt [4]{a + b x^{4}}}{221 b} + \frac {x^{16} \sqrt [4]{a + b x^{4}}}{17} & \text {for}\: b \neq 0 \\\frac {\sqrt [4]{a} x^{16}}{16} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.80 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=\frac {{\left (b x^{4} + a\right )}^{\frac {17}{4}}}{17 \, b^{4}} - \frac {3 \, {\left (b x^{4} + a\right )}^{\frac {13}{4}} a}{13 \, b^{4}} + \frac {{\left (b x^{4} + a\right )}^{\frac {9}{4}} a^{2}}{3 \, b^{4}} - \frac {{\left (b x^{4} + a\right )}^{\frac {5}{4}} a^{3}}{5 \, b^{4}} \]
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Time = 0.28 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.71 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx=\frac {195 \, {\left (b x^{4} + a\right )}^{\frac {17}{4}} - 765 \, {\left (b x^{4} + a\right )}^{\frac {13}{4}} a + 1105 \, {\left (b x^{4} + a\right )}^{\frac {9}{4}} a^{2} - 663 \, {\left (b x^{4} + a\right )}^{\frac {5}{4}} a^{3}}{3315 \, b^{4}} \]
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Time = 5.52 (sec) , antiderivative size = 55, normalized size of antiderivative = 0.69 \[ \int x^{15} \sqrt [4]{a+b x^4} \, dx={\left (b\,x^4+a\right )}^{1/4}\,\left (\frac {x^{16}}{17}-\frac {128\,a^4}{3315\,b^4}+\frac {a\,x^{12}}{221\,b}+\frac {32\,a^3\,x^4}{3315\,b^3}-\frac {4\,a^2\,x^8}{663\,b^2}\right ) \]
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